(2x^2-6)*4/129

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Solution for (2x^2-6)*4/129 equation: 


x in (-oo:+oo)

(4*(2*x^2-6))/129 = 0

( 2*x^2-6 )

2*x^2 = 6 // : 2

x^2 = 3

x^2 = 3 // ^ 1/2

abs(x) = 3^(1/2)

x = 3^(1/2) or x = -3^(1/2)

( 4 )

4 = 0

x belongs to the empty set

x in { 3^(1/2), -3^(1/2) }

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